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#1: bugaboo (bugaboo) on Jan 25, 2013 [HINT]

there might be a better way to solve the rest but what i did was this
after initial ll:
el on r5 (if you assume the 2 black pixels in c9-10 to be part of the 5 clue in that row then 2 moves later you have errors in r3) and thus you can make r5c11 a dot
ll to finish
no guessing

It's all Greek to me.:)

Comment Suppressed:Click below to view spoilers

i already had that dot
it is from that point that my explanation starts (hence i said "after initial ll" which is what gives you that dot in r5c8)

Yes, I see it. Thank you.

Good one Brian,very funny Norma.:)

The line logic on r5 is worth pointing out. It has two blocks of two pixels each. The leftmost one is definitely part of the 3 clue. The second block is either the 2 or the beginning of the 5. Either way there is a white directly to the left of it (r5c8).

To continue, I looked at that same line like bugaboo, but placed the 2 in c6-7. That forces both the 6 in r3 and the 5 in r5 past c11, causing a conflict in that column.

That means the two pixels in c9-10 is the 2, and r5c6-7 &11 are white. LL to finish.


Here's a link to the video explaining this (tau, that is, not my logic):
http://www.youtube.com/watch?v=jG7vhMMXagQ

(Why pi's wrong not mathematically, but conceptually.)

Found to be solvable with moderate lookahead by infrapinklizzard.

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