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Comments on Puzzle #20729: In Mr. Polie's Crib.
By Aldege Cholette (Aldege)

peek at solution       solve puzzle
  quality:   difficulty:   solvability: moderate lookahead  

Puzzle Description Suppressed:Click below to view spoilers

#1: Norma Dee (norm0908) on Jan 1, 2013

Cute. You're getting to be quite the authority on children's programs.
#2: Tom King (sgusa) on Jan 1, 2013 [HINT]
Aldege, I think it requires guessing (deep lookahead as I could see it moving 3-4 moves ahead). Particularly the 2 in c12 and the 2 in row 9. I didn't rate solvability, and I didn't want to take an hour seeing if I missed something.
#3: bugaboo (bugaboo) on Jan 1, 2013
after initial ll:

no matter where the first 1 clue in r2 goes (either c1 or c2) r1c1 is always a dot
lots of ll
of the 2 empty squares in r5c5 and r5c6, one must be a black and the other must be a dot, in some order
no matter where the first dot in r5 goes, the 2 clue in r12 always will be placed in c5-6
ll to finish
no guessing
#4: Tom King (sgusa) on Jan 2, 2013
Thanks, Bug. I spent a bit of time on it, but couldn't place c12 and couldn't take more time. I'll revisit it tomorrow.
#5: Aldege Cholette (aldege) on Jan 2, 2013
Yes I suppose I am,lol. Thx Norma.:)

Thx Tom and Bug.:)
#6: David Bouldin (dbouldin) on May 29, 2014 [HINT]
same start as bug:

after initial ll:

no matter where the first 1 clue in r2 goes (either c1 or c2) r1c1 is always a dot
lots of ll

then my finish:

2 in R12 can't go right or it violates R5
ll to finish
#7: Web Paint-By-Number Robot (webpbn) on Sep 27, 2016
Found to be solvable with moderate lookahead by infrapinklizzard.
#8: Joe (infrapinklizzard) on Sep 27, 2016 [HINT]
el 15 c1 - it can't go above r4 without a conflict in c2, so c1r18-19 must be black.
ll
el 9 r1 = r1c12 w
ll
extended edge logic (pseudo smile logic) on the 9 in r1 - if it were to go all the way left it would leave no room for the 1 in r2, so r1c1 must be white
ll
Summing c8&9 gives three pixels to be placed. Due to the crossing clues, that would have to be a 2 and a 1. We know that there has to be a 1 in there in r5, so the 1 in r11 cannot be in there. So r11c8-9 must be white.
Then
three-way logic on the 1 in r11: if it is in
>c3 then r9c3 will be white
>c4 then r9c4 will be white
>c6 then the 3 in r10 will be pushed left making r9c3 white
= so the 2 in r9 cannot fit there and must go in c8-9
ll to finish


I was not able to follow either bugaboo's or David's at the end. With bugaboo's, placing the 1 in c5 would force the 2 into c8-9. With David's putting the 2 on the right would still be fine compared to r5 as there are still two 1s loose in c9.
#9: BlackCat (BlackCat) on Jan 5, 2022
I see the faces but not the appliances. Had to guess 3 times.

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