Puzzle Description:

I believe her name is Kim Kardashian

#1: Nancy (nbarsi) on Mar 15, 2012 [SPOILER]

The guessing part is if K.K. is the leader or the ET!

Cute! And I agree with Nancy :)

after line logic (with line logic after each step):

at least one of r12c2/r12c3 (or both) must be green, AND at least one of r14c2/r14c3 (or both) must be green but they cont both be in c3 so at least one of them (or both) must be in c2 so c2r12-14 are green (left half is now done)

at least one of r9c13/r9c14 (or both) must be green, AND
at least one of r10c13/r10c14 (or both) must be green, AND
at least one of r12c13/r12c14 (or both) must be green, AND
at least one of r13c13/r13c14 (or both) must be green but they cant all go in c12 so we know that the green pixel in r11c14 is part of the 5 clue

no matter where you place the two green 2 clues in r12 and r13, a green will always be in either r12c13 or r13c13 which means that the green pixel in r11c13 is part of the 3 clue and you can dot r3-8c13

then i felt stuck and resorted to using a summing technique in the upper right corner looking at the box from r3-8 with c15-20
there are 6 clues in those 6 rows which correspond to 1 clue in each of those 6 columns but the 2 dots in r8c19-20 only allow c3-7 to be used (5 columns); the sum of the 6 clues in the columns is 12 and the sum of the 6 clues in the rows is 11 so the 2 in c20 must start in r3 since there are fewer available rows to fit the greater number of clues in that region
line logic to finish

there might be an easier way to solve this (hopefully)

Comment Suppressed:Click below to view hints

i did overlook the possibility of the 8 clue extending up into the summing region but if that were not a factor it could still work; if the green 1 clue goes in r3c12 then the summing is even more obvious and easier to see

anyway the step where you dotted r7c14 is easily more than a 2 step look ahead but assuming we dont even use that step
how about this: if the 8 goes up to r6 the first "move" after that is placing the 2 clue above it in r3-4 and the second "move" is placing dots in r4c19 and r6c19 (which violates c19) so the 8 clue goes down at least one more row into r14 (more line logic)

then the green pixels in r9c14 and r10c14 are part of "2" clues in their rows but they cant both go into c15 so at least one goes into c13 (make r10c13 green)
more line logic

see if you can do more with that but i am stuck again (maybe just too tired)

Comment Suppressed:Click below to view hints

Found to be solvable with moderate lookahead by wombatilim.

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