Puzzle Description:

#1: Kristen Vognild (Kristen) on Feb 21, 2012 [SPOILER]

I'm not convinced that I solved this without guessing, but I made two leaps of faith that turned out to be correct: one on the 9 clues, and another on the 7 clues.

The title makes me think of Hayley Mills (and Hayley Mills) singing "Let's Get Together." :)

I also guessed on the 9s and the 7s. I think it would also work with the opposite choice in those areas. Is the solution unique, Travis?

oops

bruce yes it says "Definitely has a unique solution" but not ll

Okay, I tried it with the 9s in the opposite corners, but I went through 10 steps or so before I got a red dot. That's a serious lookahead, though it was simple to start over.

i am really trying hard to see if this one is logically solvable without leaps of faith or looking ahead in a trial and error manner and i only have 52 black pixels so far...and that's with several moves of look ahead, but not of the trial and error variety...meaning it is more like; by looking this move ahead we know "such-and-such"...now if we look here while knowing "such-and-such" then we know "this or that" and by using "this or that" knowledge along with the dots in this line, then this square will always be black. i'll elaborate more if i can get this to solve, but it's a bit pointless to describe it all out if it still doesn't work.

i shouldn't say "pointless" because somebody else could find the next move...what i should have said was i don't want to.

I was able to place the 9s in c1&21 w/o too onerous lookahead (but more than is permissible for "logical"), but then with 112 black, I'm stuck.

Placing the 9s:
After row 10 is filled in with dots, the 9s in c1 and 21 can go either above or below that row. Note that due to horizontal clues, the next 2 columns must also be in that same quadrant.

Eg. if the 9 in c1 were to go in r1-9, then the 7 in r1 would correspond to the top 1 in c2 and the 1 in c3. Also, the 5 in r5 would then correspond to the other 1 in c2 and the 7 in c3.
Likewise, if the 9 were to go in r11-20, then the 3 in r20 would correspond to the bottom 1 in c2 and the 7 in c3. Also the 7 in r10 would then correspond to the other 1 in c2 and the 1 in c3.

With the proof that the 1,7 in c3 must be in the same section, we can then use edge logic to see that if the 9 in c1 (and thus the 1,7 in c3) were to go in r1-9, the crossing clues in r1,3,5 and 7 would make four black pixels in c4. (The hardest bit to see in that is the 1,3 in r7.) This is a conflict with the three 1 clues in r3, so the 9 in c1 must be in r11-20.

Then line logic allows quite a bit more, up to 112 pixels black. But then I'm stuck. I don't see a way forward with the 7s in r1 & 20.

i couldnt get this one logically

When it says " definitely has a unique solution" that is not the same as "solvable by logic alone".:)

shortly after my comments i made a small break and got some more pixels. looking at joe's hints this morning, that is exactly what i was doing but didn't have time to type out. so i looked back at my saved puzzle and have exactly 112 blacks also. i'll assume they are the same 112 and let everybody know if i find any others.

i'm out for now.

I guessed wrong with the nines and started over. I guessed right with the sevens. The rest solved logically. Perhaps a couple of well placed color pixels would eliminate the need for any guessing. But HEY, It's not my puzzle.

I like the result Travis.

Had to guess on the 9's at C1 and C21 and on the 7's at R1 and R19. The rest solves with linear logic alone.

Nice image/pattern. Too bad it requires guessing. At least the guessing was easy. :-)

New version published by bigblue.

I got the new version, so didn't have any problems. Like the pattern.

:)

Ditto Norma!

:D

no probs

:)

No problems LLS solving with the new version. Guessing a bit never bother me though, I like playing with it actually. Nice design in the end, looks like a piece of old fashioned soutache braid, but goes with the title too.

thanks susan :)

I'm assuming Joe's comments are from before the revision, as I had no problem with the rest once I got the 9's placed. As for the 9's, I did it through logic, but a bit differently from Joe's method.

I already figured out that the 2 columns next to the 9 had to stay in the same quadrant, the same way Joe did. When I worked on R8, I had B?B?BWBWB from C7-C15, based on the vertical clues. I knew the 9 had to go in either the first or last column, which would make the B?B?B into either BWBBB or BBBWB depending on where the 9 goes. This meant that C2-C6 were definitely white, and C16-20 were also white.

Since R8C3 was white, the 7 could only fit in the lower quadrant, solving all the 9's. The rest solved with LL.

Yes, you can look at the "previous version," if you go back and "peek at solution" (both are hyperlinks, in blue).

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