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#1: Kristen Vognild (kristen) on Nov 15, 2011 [SPOILER]

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i struggled trying to find a good way to solve the last bit of black logically
edge logic on the 6 in r35 (line logic)
two way logic on the 4 clue in r33 to get a few more dots
then stuck?

Nice image Joshua.:)

I like the image. Same as comment #2 but I used some extended logic on the 5 in row 34. There may be some logic after that, but I'm not totally sure. Fun solve though.

Found to be logically solvable by gator.

I used edge logic on row 35 to make R35C26-R35C32 dots. A little line logic.

Look at R34C26-R34C28. Either the 3 or 5 clue could go here, but in either case this makes row 33 invalid. So R34C28 is a dot.

Next I looked at row 35 again. There are only so many places that the 6 clue can go without causing row 34 to be invalid. Looking at what is in common for those, R34C13-R34C15 will always be dots.

Next I saw that either R33C13 or R35C13 had to be black. So this makes R32C14-R32C15 dots for either case.

Next I saw where the 2 clue in column 30 had to be completed with either R32C30 or R34C30, this causes R33C31-R33C32 to be dots in either case. A little line logic.

Now let's look at columns 20 and 25. Both 2 clues cannot be in row 33 without making the row invalid. So R35C20 or R35C25 (or both) has to be black. In either case, R35C20 will be black. The rest solves with line logic.

Great solve!

thanks for the hints

Tough, fun solve. The image really made me nice. I feel that attitude quite often.

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