Puzzle Description:

The "Grizzly" Bear

#1: paul dahmer (paul) on Jun 27, 2011

a real "posser" - lots of backtracking, but ultimately solvable and has a unique solution with no guessing.
Great job - lets get more of these on the site and less of
the coloured junk with no difficulty.

Definitly has that Grizzly/Kodiak body-type. Nice.

Paul, did you mean "poser"? Yes it is. Maybe as a kindness to newer puzzlers you could outline the lines of logics you used to solve this one, because at least one person marked this as "some guessing".

I couldn't do it.

Here's where I got stuck even after some involved logic in the upper left that might not make the general threshold for "logicality". http://postimage.org/image/1nyizfvz8/

Thanks for commenting you two. I didn't get quite as far as Infrapinklizzard's picture shows, just most of the main outline form and shading. If you two couldn't solve it through logics either, then I'm in good company.

My last saved puzzle looks a lot like your image, Joe! :D

i couldnt see the image at all other than for a vague outline of a body of some sort

i also could not solve this logically

I'm in good company you gang!

I got as far as Joe. Too bad, a little work on it could have made it solvable.

Found to be solvable with deep lookahead by gator.

backtracking is guessing - but guessing wrong.

Gator, please share your method.

after some some some some guessing. SOLVED!!!!

I tried this again, and believe I have a (barely) moderate lookahead solution:

After line logic, (make sure to mark c15r27 white)

you get nearly to my first picture (in #4)

Edge logic on the 3 in r1 makes c22-24 white.

Two-way logic on the 2 in r14: no matter whether c9 or c10 is black (and at least one must be), c10r13 will be black. Then LL

Extended two-way logic on the 5 in r4: (2way + one step)
-if it goes in c16, the 7 in r5 goes into c23 and then c23r9-11 are white
-if it goes in c21, the 2 in c21 makes the 2 in r6 go into c23 and then c23r10-11 are white
=either way c23r10-11 are white. Then LL

Extended edge-logic on the 4 in c23: (EL + one step)
if it were in r2-5, the 5 in c22 must be in r5-9. That forces c23r7 to be black, conflicting with c23's clue. Therefore c23r2 is white.

Lots of LL

Look at row 9. there can be a maximum of one pixel in c18-20. Now let's do some anti-edge-logic. (Instead of placing pixels, we'll try placing spaces.)
If both r7c18&19 are white, this will force BOTH r9c18&19 to be black. That is impossible. Since we know that both of r7c18-19 cannot be white, *one of r7c18 or c19 MUST BE black*.
=Whichever is black must be part of the 2 in r7, so the pixels at r7c15-16 must be white and r7c23 must be black.

Then line logic to finish.

Well, I had pictures to go with this, but I hadn't saved them when the program crashed, so buh-bye pix. D:

here was my solve (with LL to start, including C11R13, and in between each:

no matter where 2 in R4 goes, C10R13 is black
EL 3 in R1 dots C22-4R1
whether C22R3 or C22R7 is black, C23R3 is a dot
whether C26R11 or C28R11 is black, C26R18 is black
IEL 4 in C23 (watching the 4,1,1 in C25) dots C24R2-3

same step joe describes in "Extended two-way logic on the 5 in r4..."

IEL: C18R7 and C19R7 can't both be dots or it violates R9. if either is black, C18R7 has to be.

LL to finish. FUN SOLVE!!

I can't see it.

Very enjoyable even though it was a bit of hard work.

I have to agree with BlackCat. I am having trouble seeing any image in the finished picture. Can anyone help me out? Like, where's the head located, to start.

The head is at the upper left. It's a 3-quarter profile, with the bear coming toward us. :)

Okay, I see the legs and big body now. I still don't really see a face, but everything else has come into view. Thanks, Kristen. ^-^

I think that's its nose at the far left, but maybe it's been a tardigrade this whole time.

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