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#1: Ron Jacobson (shmily999) on Jun 1, 2011 [SPOILER]

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color logic to get all but the green inside the "r" and then edge logic to solve that last green part
no guessing

bugaboo - can you describe the edge logic that you used? I'm having a hard time finding some that is not 3 moves ahead.

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Aha, I figured that wasn't just an I :)

If you try to start the last green section at the top, the numbers don't come out right. You have to start with the 1 at the bottom to get the 4 to work.

you can use edge logic on the green 2 clues in r9 and r10
i will be very deliberate so you can tell me how many steps ahead this actually is (because i dont think it has ever actually been clarified on this site what constitutes a "step")
does a step include any dots/pixels that can be immediately placed as a direct result of placing another dot/pixel (or set of dots/pixels?)

lets say we place the green 2 in r9c5/6
we must dot r10c6
we must place a green in r10c5
(this is all one step is it not?)
the next 2 moves can be done in either order and still constitute one step as they simultaneously occur
we must place a green in r10c4 and
we must dot r9c4
this gives the error (2 moves ahead)

technically, should placing the dot in r9c4 after placing the green 2 clue in r9c5/6 actually count as part of the first step? if so then this edge logic is technically is only even just one move ahead

repeat similar logic in r10 on the green 2 clue
then repeat similar logic on the green 2 clue in r13

Thanks. That does it.

This is how I think about "moves ahead":
Place either a cell or set of cells (either as filled in or as dots - most of the time we fill in though).
Now for 1 move ahead, look for any cells that are filled in or dotted as a direct result of the previously places cells.
2 moves ahead would be direct results of the initially placed cells or from the 1 move ahead.

So in your first edge logic:
Initial: R9C5-R9C6 green
1 move ahead: R9C2-R9C4, R10C6, and R13C5-R14C6 (4 dots) are dots, R10C5 is green
2 moves ahead: row 10 makes R10C5 green, but column 5 makes R10C5 a dot (contradiction)

Found to be logically solvable by gator.

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