Puzzle Description Suppressed:Click below to view spoilers

#1: Web Paint-By-Number Robot (webpbn) on Apr 7, 2010

Found to be logically solvable by Gator.

Most of the puzzle solves with line logic. I then used edge logic in row 20 to see that R20C21 and R20C21 were dots. The same kind of logic can be used in rows 6, 10, and 16 to see that R6C23, R10C23, R16C21, and R16C22 are not part of the 5 clues in those rows (but they aren't necessarily dots either). But knowing this, R6C18, R10C18, R16C26, and R16C27 are red. A little more line logic.

Now look at the 5 clue in column 23. It only has two places to go. Let's try the bottom. Look at how this affects column 28 (looking 1 move ahead for each row). It will make R16C28 a dot, R17C28 red, and R19C28 a dot. This makes column 28 invalid as we cannot place the 3 clue, so the 5 clue in column 23 must go up top. The rest solves with line logic.

Easy puzzle to guess the solution, but much harder just using logic. I liked it. :)

Didn't look fun.

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