Puzzle Description:

Reactor. You're the green thing, pushing red things into the wall--or, better, the black and red pegs that cool down the slowly expanding reactor.

#1: Andrew Schultz (blurglecruncheon) on Sep 23, 2025 [SPOILER]

Here is the soundtrack of Reactor: https://www.youtube.com/watch?v=p4DtLBdC9a8

This was obviously much too hard without the extra bits. You'll want to clean up the red bits in the upper left. The blue edge logic also does a lot, and you can also use color logic to put the green/black core in place.

The next bit is tricky to know where to look, but once you do, it's not bad at all.

Color logic: R9 C12-14 must be dots. R11C12 must be a dot. R8C11-15 must be dots. R7C12-15 must be dots. That places a blue at R5C12.

R4C11 must be a dot, or we get a contradiction in R2C3-15. That puts a blue at R5C11.
R4C15 must be a dot, or we have nowhere for the first blue in C12.

The helper gets us to 84%.

Then R42C10 is a dot. Also R45C12 is a dot. Helper, R39C11 is a dot. Helper solves the puzzle.

Found to have a unique solution by blurglecruncheon.

Found to be solvable with moderate lookahead by blurglecruncheon.

huh. I completely missed this game.

So initial line & color logic and edge logic got me to 72%, including the color logic here:
"R9 C12-14 must be dots. R11C12 must be a dot. R8C11-15 must be dots." However, "R7C12-15 must be dots" is not accurate at this point, because there's still an unplaced black in C39 that could potentially go into R7, and R7 C12-13 could potentially be the blue 2. (R7C14-15 are already dots from the LL that came after EL on the 5 in R1.) This makes your next step, "R4C11 must be a dot, or we get a contradiction in R2C3-15," invalid, so I'll try to pick up from there and see if there's an alternate path.

C13: If the top blue 2 is placed in R6-7, R4-5 C10-11 will be blue. If the top blue 2 is placed within R3-5, R4 C12-13 and R5C12 will be blue. (Attempting to place it in R5-6 makes C11 invalid.) Either way, R4-6 C2-9 are white, which marks R8C8 blue. L&CL finishes the first blue in R8 and places the reds in R8&10.

R4: If the first blue 2 is placed in C11-12, R6 is invalid. If it is placed in C10-11, R6-7 C12-13 are blue. If it is placed in C12-13, R6 C10-11 and R7C10 are blue. Either of these marks R7C8 white. LL.

I'm having trouble finding a way forward from here.

New version published by blurglecruncheon.

Found to have a unique solution by blurglecruncheon.

Found to be solvable by line and color logic alone by blurglecruncheon.

Sorry about that oversight. I moved one small clump to the edge so I think it's a lot easier--I checked twice.

Found to be solvable with moderate lookahead by wombatilim.

I agree, the only lookahead needed now is some EL.

I've never heard of this one either. The soundtrack was kind of cool, though.

Goto next topic

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