Puzzle Description Suppressed:Click below to view spoilers

#1: Andrew Schultz (blurglecruncheon) on Sep 23, 2025 [SPOILER]

Comment Suppressed:Click below to view spoilers

This was obviously much too hard without the extra bits. You'll want to clean up the red bits in the upper left. The blue edge logic also does a lot, and you can also use color logic to put the green/black core in place.

The next bit is tricky to know where to look, but once you do, it's not bad at all.

Color logic: R9 C12-14 must be dots. R11C12 must be a dot. R8C11-15 must be dots. R7C12-15 must be dots. That places a blue at R5C12.

R4C11 must be a dot, or we get a contradiction in R2C3-15. That puts a blue at R5C11.
R4C15 must be a dot, or we have nowhere for the first blue in C12.

The helper gets us to 84%.

Then R42C10 is a dot. Also R45C12 is a dot. Helper, R39C11 is a dot. Helper solves the puzzle.

Found to have a unique solution by blurglecruncheon.

Found to be solvable with moderate lookahead by blurglecruncheon.

huh. I completely missed this game.

So initial line & color logic and edge logic got me to 72%, including the color logic here:
"R9 C12-14 must be dots. R11C12 must be a dot. R8C11-15 must be dots." However, "R7C12-15 must be dots" is not accurate at this point, because there's still an unplaced black in C39 that could potentially go into R7, and R7 C12-13 could potentially be the blue 2. (R7C14-15 are already dots from the LL that came after EL on the 5 in R1.) This makes your next step, "R4C11 must be a dot, or we get a contradiction in R2C3-15," invalid, so I'll try to pick up from there and see if there's an alternate path.

C13: If the top blue 2 is placed in R6-7, R4-5 C10-11 will be blue. If the top blue 2 is placed within R3-5, R4 C12-13 and R5C12 will be blue. (Attempting to place it in R5-6 makes C11 invalid.) Either way, R4-6 C2-9 are white, which marks R8C8 blue. L&CL finishes the first blue in R8 and places the reds in R8&10.

R4: If the first blue 2 is placed in C11-12, R6 is invalid. If it is placed in C10-11, R6-7 C12-13 are blue. If it is placed in C12-13, R6 C10-11 and R7C10 are blue. Either of these marks R7C8 white. LL.

I'm having trouble finding a way forward from here.

New version published by blurglecruncheon.

Found to have a unique solution by blurglecruncheon.

Found to be solvable by line and color logic alone by blurglecruncheon.

Sorry about that oversight. I moved one small clump to the edge so I think it's a lot easier--I checked twice.

Found to be solvable with moderate lookahead by wombatilim.

I agree, the only lookahead needed now is some EL.

I've never heard of this one either. The soundtrack was kind of cool, though.

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