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Comments on Puzzle #35672: Viola
By Michael B (alethius)

peek at solution       solve puzzle
  quality:   difficulty:   solvability: line & color logic only  

Puzzle Description Suppressed:Click below to view spoilers

#1: Bill Eisenmann (Bullet) on May 23, 2022 [SPOILER]

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#2: Alan Lafond (Cural) on May 23, 2022 [SPOILER]
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#3: Norma Dee (norm0908) on May 23, 2022
As a trombone player I had to learn the alto cleff. I was never really comfortable with it.
#4: Belita (belita) on May 23, 2022 [SPOILER]
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#5: Michael B (alethius) on May 24, 2022
It's my instrument :-)
It's the clef that we use to read music (fits perfectly between treble and bass)
I may be biased, but I think it's a wonderful instrument, though it's harder to project than violin. It's mellower and usually softer.
#6: Kristen Vognild (kristen) on May 25, 2022
I played an eighth size cello, in 2nd and 3rd grade, so it really wasn't much larger than a viola. :)
#7: Ailsa Hebert (bazette3) on May 25, 2022
Excellent puzzle! Loved the solve....well thought out! Thanks!
#8: Koreen (mom24plus) on May 27, 2022
My sister plays the strings and I play the woodwinds. I wondered if the trombone used the alto clef. Seems like the baritone would too? or maybe not, if it's not a C instrument?
#9: Andrew Schultz (blurglecruncheon) on Aug 20, 2022 [HINT]
The color logic was really interesting here! There's an odd sort of symmetry the way I solved it. I hadn't seen it before. Maybe someone has something simpler, but I had fun with my own solve. I hope this is coherent.

I was able to work on column 10. C11 has black squares at R9-11 and then you get contradictions if C10R10 is a dot.

Note if you try to place a black square above it without any red square between, you get a contradiction, so there must be a red above it and below it. But now there is a black/red/red/black either below or above r9-r11. Either way, we run out of squares where to place the first black. So R10 is not a dot. But we have a similar argument if C10R10 is red. The black/red/red/black must be either above or below it. Either way, the black is at least 2 squares away, leaving no room for the red/red/black.

So C10B10 is black. That fills in C9R10 and C10R9/11 as red. But then the two remaining black squares only fit in R2 and R19. So line/color logic solves the rest.

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