Comments on Puzzle #27450: Can I assist you?
By Tom O'Connell (sensei69)
peek at solution solve puzzle
quality: 
difficulty: 
solvability: moderate lookahead
peek at solution solve puzzle
quality: difficulty: solvability: moderate lookahead
Puzzle Description Suppressed:Click below to view spoilers
#1: Jota (jota) on Feb 7, 2019
Yes, please I'm looking for Tom.#2: Web Paint-By-Number Robot (webpbn) on Jun 28, 2020
Found to have a unique solution by infrapinklizzard.#3: Web Paint-By-Number Robot (webpbn) on Jun 28, 2020
Found to be solvable with moderate lookahead by infrapinklizzard.#4: Joe (infrapinklizzard) on Jun 28, 2020 [HINT]
After LL leaves only four more black pixels to be placed,#5: Michael A Rodgers (marodgers) on Jul 31, 2020 [SPOILER]
If c10r10 were black, it would force both c12r10 and c12r14 to be black making a conflict. So c10r10 must be white.
LL to finish
Comment Suppressed:Click below to view spoilers#6: Andrew Schultz (blurglecruncheon) on Jul 7, 2021
I bungled things my first try, and the eyes were really askew. It was freaky but amusing. A nice pleasant solve.#7: Joanne Firla (JoFirla) on Apr 15, 2023
R.I.P. Tom O'Connell. Thank you for sharing your talents with this website. You will be missed.#8: Joanne Firla (JoFirla) on Apr 15, 2023
See puzzle #36695.#9: Bill (PopPop ) on Jun 6, 2023 [HINT]
Nice solve.
I did it a little differently when LL runs out. I looked at the 2 in R14 - you already have one pixel filled in, and whether the 2nd one goes to the left or to the right, either way C9R10 will be black.
Show: Spoilers
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