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#1: Jota (jota) on Jun 9, 2019

I have marked this entry as requiring look ahead, but it will be unfair not to award a prize if this is not the case. Please help!

Found to have a unique solution by valerie.

i solved with only LL. whether they are necessary or not (pretty sure the second one at least isn't needed), here are the two trickiest moves i made:

- whether the blacks in C5-6R4 are part of the 2 or 3 clue, C3R4 is a dot either way

- (much later) whether the blacks in C15R8-10 are the 3 or the blot, C15R7 is a dot

Solved with line logic and blot logic.

First bit of blot logic R10 has 2 groups of 3 at C16-18 and C23-25 the left group must be part of the 6 so the right group must be part of the blot. This makes R10 C26-28 black and allows you to fill in the 6 and 2 clues for that row.

More line logic then I came to a point there were 4 groups in R4 but only 3 clues, so the rightmost groups must be part of the same blot. This filled in R4 C27-32 as black.

more line logic then in R2 there are 3 groups and 2 clues, the right 2 groups must be part of the same blot. Filled in R2 C19-22 as black.

Line Logic to finish.

It's still marked as ?

there you go! fixed it ;)

Thanks David but I still see the ?

ah...didn't look at it on the list, just the solvability switched from guessing to moderate, but i guess it can still be in question. which makes sense since an admin hasn't determined it yet. i thought the votes could tip it. i'm not very knowledgeable on the inner workings :P

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Found to be solvable by line logic alone by valerie.

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Looks as if someone caught a critter (racoon? mouse?) in their house, and they're going to let it go in the woods.

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