Puzzle Description:

With a final tally of scoring to date, and with great appreciation to Tom (sgusa), the results are in...

#1: Kim (kjh) on Jun 8, 2014

With One Win Each: Linda, Leann, Amy, Richard, Dan, Kathy, Belita, Alison and Travis.
With Two Wins: Kurt
With Three Wins: Besmirched Tea
And with 22...me
Tom, again, this series has been a great deal of fun and you have my sincere appreciation. Congratulations to all!!

Anyone notice my name is not in the winning list. Some music lover I am.ha,ha.:)

Ah, Aldege, I think I shall have a special puzzle just for you. And, I should make a list of how many times you stumped me!!

good one kim :)

Couldn't solve w/o guessing, but i'll wait for the experts.

Good one Kim

it solves with summing, Jota.

color logic places the blue and red.

el the 3's, and you can get the whole zig zag line from the 3 in r 20 starting bottom middle to left edge of puzz...from here, you still have a triangle not dotted in the lower left of grid and another square-shaped space not dotted on the lower right. with me so far?

look at the black clues remaining in r's 16-20. they add up to a total of 10. now look at the black clues remaining under the blue in c'15-19. they add up to 9. therefore 9 of the remaining 10 in the lower r's must lie in your un-dotted square in the lower right in c'15-19. since you know this, you can dot the entire lower left triangle that remained un-dotted. the last unaccounted-for black must be in c20 then(under the blue, somewhere in r's 16-20--only one place it can be(r16,c20), since there's only one). you should be able to finish from here with normal logic

oh yeah, good one Kim :)

And Kurt has spoken! I didn't mark it as guessing BTW.

there are a lot of better solvers out there than me...

but that's how I did it. explanation make sense to ya?

Sorry for the difficulty, Jota. Thank you for the explanation, Kurt...I couldn't have said it better myself. Actually, I couldn't have said it at all! which is why I admire all you "real" puzzle solvers - compared to me who just stumbles through...

I only zigged and then I zagged

Total sense Kurt! I love difficult Kim!

Thank you kindly, Jota.

Fun! Don't think this is guessing but I want some verification of my "proof."

Reds and blues get placed with color logic. Dots in R7-9 left and C14-16 down too. R1C6 and R15C20 are black dots, which is important.

How to place the 3 in R20? Edge logic pushes it to R8 at least. But there's no room in R15-19 for the 3 and 2. So we can place it at C9/10.

Now the zigzag falls due to line logic.

Now if R16C20 is a dot so is R1720. The remaining box in R16-20 C15-20 can only be filled row-wise by 2's. So that means an even number of black dots counted that way but an odd number counted from C15-19 (1,2,2,2,2). Contradiction! R16C20 is a black dot.

Similarly if R17C20 is a black dot we get an odd/even problem.

Line logic fills in the zigzags.

Marking this not-definitely moderate lookahead though my solution feels right. Something always might be off.

Goto next topic

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