Puzzle Description:

Don't forget to count Olive - the other Reindeer ("all of" the other reindeer). This mondegreen is so well known Olive even got her own book and TV special. - Had to get in one last Christmas reference. Happy Twelfth Night!

#1: marjorie rex (mamo) on Jan 5, 2014

hahaha

can't believe I'd never heard that one before!

nice solve! no guessing needed...

Very well known mondegreen. Love the puzzle

I obviously need to get out more often,I've never heard this one before. Cool image Heather.:)

I hadn't heard it either. Funny.

So how many?

11 reindeer....According to the song, "Rudolph the Red-Nosed Reindeer", Santa has eleven reindeer? Sure, in the introduction it goes "There's Dasher and Dancer and Prancer and Vixen, Comet and Cupid and Donner and Blitzen..." That makes eight reindeer. Then there's Rudolph, of course, so that makes nine. Then there's Olive. You know, "Olive the other reindeer used to laugh and play" That makes ten. The eleventh is Howe. You know, "Then Howe the reindeer loved him..." Eleven reindeer. The proof is in the song

Very funny travis. Good old reliable Howe. Oh, how we love him.

:)

Thanks Travis - I'd completely missed Howe! :)

Cute and clever! Thanks Heather/

http://www.imdb.com/title/tt0227173/
:)

Fun puzzle and pun.

Edge logic but it isn't terribly clear where to start.

You can fill in the reds. dots at C3/5 R13 are important, too, because each way logic knocks out greens in C15-20. Helper gets you to 19%.

In C1 we can chip away from R18 to R16. Helper to 42%.

R2C13 green creates a quick contradiction in R9 with C1 green and C2 a dot. Then, line logic.

Found to be solvable by line and color logic alone by blurglecruncheon.

Hm. Andrew and I both used advanced logic to solve it, so I'm going to change it to say Moderate Lookahead.

Here's how I solved it:

Line and color logic got me to 7%. The puzzle is marked "Solvable by line and color logic alone," but I don't see a way forward from here without advanced logic.

I did internal edge logic on the 6 in row 19.

Line logic to 19%.

Edge logic on the 4 in column 1.

Line logic to 25%.

Column 12 had a green at row 7. Whether it's part of the 1 or the 2, row 9 has to be blank. The same logic for column 9.

In column 11, if the green in row 7 is part of the green 1 or the 3, row 4 has to be blank.

Line logic to 28%.

In column 12, if the green 1 is in the 1 or the 2, row 5 has to be a dot.

Now I'm at 29%.

Internal edge logic on the 13 in column 17.

Line logic to 42%.

In column 7, whether that green dot is part of the 1 or the 2, row 9 is blank.

Line logic to finish.

Found to be solvable with moderate lookahead by valerie.

Goto next topic

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