Puzzle Description:

#1: Joe (infrapinklizzard) on Jul 30, 2013 [HINT]

This is another blot puzzle that yields to summing.

Line and color logic leaves only red in r9-11 to do.

Sum rows 10 & 11. [2 + 2 + blot + blot + blot] = [4+ 3blots]
Summing the crossing columns(c2-8) gives us a maximum of seven. (One might be in c8r9)

Notice that the *minimum* that r10-11 can be is [4+ three blots] or 7 if all three blots are 1s.

Since the minimum of the r10-11 equals the maximum of the columns, all of the column clues *must* be in r10-11. So c8r9 is white. Then line logic finishes r8-9.

Then alternating smile logic finishes r10-11.

Found to be solvable with moderate lookahead by infrapinklizzard.

tell Ann thanks again :)

You're wrong Joe... It's a very classical example for using color logic. Without summing, whitout guessing. It can be solved mainly color logic at blots.
for example r1, r9, r20 are absolutely color logic. Look for colors!
Interesting the left side of r11-12. It's a special 2-rows counting... that is similar to edge logic but not the same, because pure edge logic cannot answer, which row is above or under. For this you don't need count squares but the number of clues.... :)

Thomas - at the point where my hint starts, there is only red left. With only one color to be placed, there can be no color logic because that is using *different* colors for placement.

What you call "2-row counting" is the alternating smile logic.

Colorful. No guessing.

Goto next topic

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