Puzzle Description:

Classic math joke - i says, "Be rational", pi says, "Get real"

#1: Gator (Gator) on Apr 1, 2010 [SPOILER]

For those not familiar with this...

"i" is what is used to denote an imaginary number which is defined as the square root of -1

"pi" of course denotes the constant 3.1415... and it falls within the set of irrational numbers

har har. fun solve though i screwed it up a few times and had to backtrack

Oh we are SUCH geeks! :)

(Thanks for the good solve and bad joke!)

It's a smaller version of #7330

Fun solve. A little better puzzle would make it easier to see.

another good one Gator, but i had to wake up to solve it

Fun solve, Gator. Good joke. :-D

Groan!

I had never heard this joke before and it made me laugh out loud! Well worth the solve!!!!

...but the title should properly be,"Pi and i get into an argument...". That way a person such as I thinks all along you've made a grammatical error only to find at the puzzle's end they were the one who was wrong lol lol lol!

Thanks!

I did the purposeful grammatical error so that people wouldn't think of the imaginary number, but I guess most people wouldn't know (or remember) what an imaginary number is. :)

ha.
enjoyable

great fun to solve...stuck to my line-logic guns and powered through it with nothing else.

9 & 10 remind me of the joke about the grocery in the college town, where a student is in the 15 items or less lane with a huge cart load of groceries, and the checker says, "lemme guess. You're either a math major and can't read, or an english major and can't count."

:-D

In response to #13: I am a cashier at a grocery store. I wish so bad that it wasn't rude to say that to a customer! Lol!

...But I don't think I could bring myself to say it to them out loud anyway.

Technically speaking i is defined as the number whose square is -1. The definition "square root of -1" leads to a paradox, as you can say -1 = sqrt(-1) ^ 2 = sqrt(-1) * sqrt(-1) = sqrt(-1*-1) = sqrt(1) = 1 hence -1 = 1.

Any calculation rules (multiply or divide) involving radicals are only valid for real positive values (>=0).

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