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Comments on Puzzle #36337: THE ALL SEEING
By cathy mcweeney (catty)

peek at solution       solve puzzle
  quality:   difficulty:   solvability: moderate lookahead  

Puzzle Description:

#1: cathy mcweeney (catty) on Jan 12, 2023

i solved this after i made it and it didnt seem to need guessing ut let me know if it does
#2: Philip (Philip) on Jan 13, 2023 [HINT]
Fun solve! Some of the EL was tough to find, but easy once you spot it.

CL/LL got me to 63%
EL on 4 in C1: C1R5,C1R12-18 are white
LL
EL on bottom 2 in C2: in all cases C3R16-17 is black
LL
EL on left 2 in R13 (look at R11): R13C5 is white
LL to finish
#3: cathy mcweeney (catty) on Jan 14, 2023
thank you but i dont understand what all that means
#4: Kristen Vognild (kristen) on Jan 18, 2023 [HINT]
I used quite a lot of zigzag logic, which can probably be described in more official terms. ^_^
#5: Eric (kelalatir) on Jan 28, 2023 [HINT]
@catty Here is a guide to the acronyms and shortcuts used in the hint post above:
CL - Color Logic
LL - Line Logic
EL - End Logic
C# - A C followed by a number means Column number. Columns are counted from left to right.
R# - An R followed by a number mean Row number. Rows are counted from top to bottom.
C#R# - This identifies a specific square based on the column number and row number. For instance C1R5 is the square in Column 1 and Row 5.
C#R#-# - This identifies a series of squares. For instance, C3R16-17 would be the two squares that are both in Column 3 from Row 16 to Row 17.

For more information on how to use the different types of logic, please check out tips shown under every puzzle. Tip 4 has information about color logic, and tip 7 refers to the advanced logic techniques such as end logic.

I hope this information is useful.
#6: Wombat (wombatilim) on Mar 15, 2023 [HINT]
C1: A combination of edge/2-way logic (C5 eliminated with EL, then 2-way involving the 2s in C2) puts blacks in R8-9. LL.

C18: At least one of R7-8 will need to be white. This places a black in R8C20. LL.

C2: EL places white in R14C2 and blacks in R6C2, R12C2, and R16-17 C3. LL.

C3: If the black in R12 goes into R11, it creates a contradiction in R13. Therefore R13C3 is black instead.

LL to finish.
#7: Web Paint-By-Number Robot (webpbn) on Mar 15, 2023
Found to be solvable with moderate lookahead by wombatilim.

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