Puzzle Description Suppressed:Click below to view spoilers

#1: Norma Dee (norm0908) on Jun 13, 2014

Thank you. I needed that!

it's easy to "see" the circular and symmetric shape and all, and it's a no-brainer to tell where the 6's go... but I'm not seeing a moderate look-ahead way to get there(though I didn't look very long or hard). Deep is no prob using any of the corners....

Cool!

Found to be solvable with deep lookahead by infrapinklizzard.

After line logic,
edge logic 6 r1 = c1, c20 white
edge logic 6 r20 = c1, c20 white
deep lookahead extended edge logic 6 r1 = c2, c19 white
deep lookahead extended edge logic 6 r20 = c2, c19 white
deep lookahead extended edge logic 6 c1 = r2, r19 white
deep lookahead extended edge logic 6 c20 = r2, r19 white

each of those 6s can now go in only one of three places, but it could go in any of them without a conflict for quite a long time.

Here's some quite deep lookahead:

The 6s in c1 and c20 can go in one of three places each (as said before). No matter which one of those three, it will trigger one of the 1s in r11. (If it goes in the top position, the bottom 4 in c2/c19 will do it; if the middle position, the 6 itself will; and in the bottom position, the top 4 in c2/c19 will.) Thus the two 6s will trigger both 1s and the rest of r11 must be white (r11c3-18 = w)

LL

EL 6 r20 = places it
LL to finish.

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