Web Paint-by-Number Forum
Comments on Puzzle #23788: An easy puzzle
By RB (rb2013)

peek at solution       solve puzzle
  quality:   difficulty:   solvability: moderate lookahead  

Puzzle Description Suppressed:Click below to view spoilers

#1: valerie o..travis (bigblue) on Feb 10, 2014

i see a bird :)
#2: Thomas Genuine (Genuine) on Feb 10, 2014
50 mp körül volt... R4C1-C3-ra néztem a valószjnűségi változót. Jelentős volt a különbség, tehát nem volt kérdés.
Ez a módszer! :)
#3: Norma Dee (norm0908) on Feb 10, 2014
You might want to go to Find Puzzles and check out the number of 5 x 5 puzzles. I stopped counting at 375. My math statistics are a bit rusty but it kind of indicates that just about everything that can be done with a 5 x 5 has already been done. The only change to some designs would only be adding or changing colors.:)
#4: Tom O'Connell (sensei69) on Feb 10, 2014
a dunce who lost the top of his hat?
#5: Joe (infrapinklizzard) on Feb 11, 2014 [HINT]
The numbers are rather astronomical, actually.

I counted 147 5x5 2-color puzzles. The possible combinations for a 5x5 puzzle (two-color only) is 2^25 or 33,554,432. Even if a full three quarters of them were excluded for being poor puzzles, there would still be around 57,000 TIMES more than what we have to date (8,388,608 to be specific).

There seem to be a further 200 3-5 color puzzles already created. There is an even more huge number of possible puzzles. 5^25 or 2.98x10^17, or 298,023,220,000,000,000. Even if the unlikely amount of 99% of these were bad puzzles it would take you 9.4 million CENTURIES to look at the rest at one puzzle per second.

This is actually a good, hard puzzle if not a good picture.

I have not found a ML solution, but with deep lookahead you can do:

After c2r4 and c4r2 are marked with LL,

The 1 in r4 can go in two places. If it were to go in c4, then:
> that forces the 2 in r4 into c1; and makes r4c3 white which
> then makes c3r2 black which
> forces the 1 in r2 into c1
= with r2 and r4 black, there is a conflict with the 2 clue in c1.
Since the 1 cannot go in c4, it must go in c5.

LL gets you another black and four whites.


and another bit of DL,

The 1 in c2 can go in two places. If it were to go in r2, then:
> that forces the 2 in c2 into r5; and makes r2c3 white which
> then forces the 2 in c3 into r3-4 which all
> makes r1c2-5 white
= leaving no room for the 2 in c1.
Since the 1 cannot go in r2, it must go in r1.

Then LL to finish.

#6: David Bouldin (dbouldin) on Apr 15, 2014
joe, i was discouraged until i noticed that your math is off by a decimal place. 940,000 centuries...which is MUCH more doable ;)
#7: Joe (infrapinklizzard) on Apr 16, 2014
Yup: 944,378 centuries, 60 years, 324 days, 11 hours, 5 minutes and 31 seconds; but that leaves no time off for good behavior.
#8: David Bouldin (dbouldin) on Apr 16, 2014
i'll have my "good behavior" time during the 1.1259 quadrillion seconds i save by skipping the ones that don't have any white in them.

also, i'm glad i'm not the only one that uses 365.25 as my default "year" in calculations :)
#9: Joe (infrapinklizzard) on Apr 17, 2014
No, no, David. Remember that we've already kicked out 99% of the puzzles - presumably for that reason, among others. So no snoozing!

365.25 is certainly close enough. I'm certainly not going to count the leap-day off every 100 years, much less the one that's actually NOT off every 400 years. And don't even consider the countless (and fairly random) leap-seconds added and sometimes subtracted by the Time People.
#10: Kristen Vognild (Kristen) on Apr 17, 2014
So... 365.24999?
#11: Joe (infrapinklizzard) on Apr 18, 2014
More like 365.2425
365days/year * 400years = 146000days
146000days + 100leapdays = 146100days
146100days - 4 century leapdays = 146096days
146096days + 1 every-fourth-century leapday = 146097days
146097days / 400years = 365.2425 days/year

And now you've made me do it. And with such a nice decimal, I might even remember it.
#12: David Bouldin (dbouldin) on Apr 18, 2014
oh no
#13: Joe (infrapinklizzard) on Apr 18, 2014
Oh, yes. See what she's done?!? She's gone and added 20 CENTURIES to the time!

944,398.00103936883701569150277885 centuries it will take now.
To break it down, that's 944,398 centuries, 37 days, 23 hours, 5 minutes and 31 seconds.

#14: Norma Dee (norm0908) on Apr 18, 2014
Wow!
#15: David Bouldin (dbouldin) on Apr 18, 2014
...OR we just adjust how long we spend on each puzzle so that we don't have to spend those extra 20 centuries. that'll free up some time in case we want to do a larger puzzle occasionally.
#16: Joe (infrapinklizzard) on Apr 18, 2014
If you can adjust your time on a 5x5 downward from ONE SECOND each, with no break in between, then I'm very impressed.
#17: David Bouldin (dbouldin) on Apr 20, 2014
i'm sure it's an insignificant adjustment :)
#18: Gator (gator) on Apr 26, 2017 [HINT]
^^Nerds :)

No matter where you place the 2 in R1, R2C2 will be a dot. LL to finish.
#19: Web Paint-By-Number Robot (webpbn) on Apr 26, 2017
Found to be solvable with moderate lookahead by gator.
#20: David Bouldin (dbouldin) on Apr 28, 2017
It's a special plane to be on when Gator calls you a nerd! ;)
#21: Valerie Mates (valerie) on May 7, 2022 [SPOILER]
Comment Suppressed:Click below to view spoilers

Show: Spoilers

Goto next topic

You must register and log in to be able to participate in this discussion.