Puzzle Description:

#1: Norma Dee (norm0908) on Jan 4, 2014

Capricorn?

agree with norma :)

yes, but Norma said it first

yes she did tom lol, good for her and what does norma win (a new tv right) :)

Edge logic on the top 2 was easy. It wasn't too bad, and the rest solved with line logic.

we are trying to do that for her trav

Nice one Tom. What exactly is the word on the t.v.for Norma. Do we have the info,and who all is going to chip in. If we get enough people maybe she can get a bigger one. Niki and I got our son A-J a 13" LCD years ago and it was just over a hundred dollars and it's been a great T.V.:)

RCA 19" Class LED-LCD 720p 60Hz HDTV, (1.8" ultra-slim) LED19B30RQ
18.5" diagonal screen size
HDMI Inputs: 1
Wall mountable
Online
$109.00
List Price:$149.99
You save: $40.99(27%)
Special Buy
•
Free Shipping available
•
Free store pickup

At Walmart!

Y'know I saw one on the curb with the words "FOR FREE" on it. Might have to pay for shipping, however...

I know this one! It's the Handicap Parking sign outside the bar.

Al, she has to reinstate her pay pal account then we can contribute .... she can use that account to purchase the above stated tv that Jota suggested.

I checked the RCA at Walmart and it gets some bad reviews. They also sell a Sceptre for $99 that gets better reviews. Also read a review after Christmas which said the Sceptre was better. I'm kind of embarrassed by all this, but finally decided it sure would be nice to have a new TV and what are friends for. I got my pay pal account straightened out. What info do you need?

we need to know the "who" to send it to

My name is actually Norma Dee. Do you need more than that?

Norma I don't know... whatever is the name on the pay pal account. I'll try Norma Dee

I think you need my email address which is norm0908@yahoo.com

okay... norma ...done deal :)

I don't have paypal, what do I do?

contact her via e-mail and you two decide, check out your msgr msg

good jota asked...i don't have paypal either

:) travis

Ok Norma,I sent my $10 in. I don't know how many people are chipping in,but hopefully you'll get enough for a t.v. If you need more let us know and we'll see what we can do. When you do get one,please let us know and I hope you enjoy it.:)

Thanks so much Aldege. Just sent you Niki and email.

Bryan: Edge logic on the 2 in r2 cannot help at the beginning. While c2-3 can be eliminated with deep lookahead, c10-11 cannot. (the 11s could go all the way left and the 2|1 in c13-14 could go in either r8-9 or r12-13.

For moderate lookahead:

After line logic,

edge logic on the 2 in c1 makes r6 white, then LL
edge logic on the 2 in c13 makes r6 white, then LL

That's it for moderate lookahead in the top for now.
{The 2 in r2 can go in any of the three spots with moderate lookahead. (The left position can be ruled out with deep lookahead.) In r5, the 1 has to be in either c2 or 3. But it can fit in either even to a reasonable deep lookahead. The 2 can be ruled out of c13-14, but only with deep lookahead.}

Let's look at r14. Note that there are not two crossing 1s for the 2 clue to hide in, so the 2 in r13 must be above the 2 in r14.
Now look at the 3. Its current range is [c5-11]. The clues that can be above it are the 3 or the 3 and the right 2 (in r13). So with that info, edge logic rules out positions c5-7 and c6-8 (because in r13, the 3 and left 2 would get smashed together) and also position c7-9 (because there's no 1 in r13).

That leaves the 3 in r14 the range of [c8-11]. And that means that r14c9-10 must be black.

Then the bottom solves with line logic. That leaves the top.

The 2s we discussed above are still approachable, but they are also still deep lookahead. So let's try the 2 in c3. If it were in r4-5, then c3r3 and r5c2 would be white. The 11 in r3 would be blocked, so c2r3 would also be white, but that would leave no room for the 2 in c2. So the 2 in c3 cannot be in r4-5 and c3r5 is white.

Then LL finish.

I'm a bit late to this, but I hope you got your TV, Norma.

Helper to 57%.

If R9C13 is a dot, so is R13C13.

If R9C13 is black, R12C10 is black, making R12C13 black.

Either way the 2 in C13 can't be in R12-13.

Helper to 91%.

Now where does the 1 in R5 go? If in R10/11 there is a 1 in R2. If in C3 we elbow out the 2 in C2. So it is in C2.

Line logic.

Found to be solvable with moderate lookahead by blurglecruncheon.

Goto next topic

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