Puzzle Description:

...they store the carrots there.

#1: Norma Dee (norm0908) on Dec 21, 2013

Sounds like they Igor's help. He thinks he's a world class burglar. heh heh heh. Nice puzzle.

Mmmm...carrots

What they stole the carrots from all the snowmen and now they want more?? Cute puzzle Tom

exactly what i was thinking susan :)

cute and funny Tom.:)

thanks guys :)

Super cute!

good job, I like it! fun solve, and no guessing!

one move I made mighta been deep, but surely everything else was mod and I might have missed an easier way. definitely no need to guess though

thx Jota & Kurt

I see this has been vacillating between deep-lookahead and guessing. This is tricky, but it can be done with moderate lookahead.

First, some internal edge logic on the 7 in r2 makes c1 and c17-20 white.
Then (after a tiny bit of line logic) edge logic on the 5 in r1 makes c10-16 white.

Now for the tricky bit:
Look at c2. The 6 has been pinned by the four pixels in r3-6. That means there can only be one more block in that column (the 5).

In c1 there's a 5 and a 3. Look at the crossing clues: there are not three 1s in a row. Therefore the 3 in c1 must trigger a block in c2 (and thus anchor c2's 5).

The upshot of this is that the 5 in c1 must be next to the 6 in c2.

Now, since the 6 in c2 cannot go past r8, the 5 in r1 cannot either (because r9 is a 2 and would make the block in r2 seven long). So the 5 in r1 is placed completely in r4-8. Then LL finishes the upper left block.

Edge logic on the rightmost 2 in r3 makes c20 white. That gives lots of line logic.

Then edge logic on the 3 in c1 makes r11-12 white,
and edge logic on the 5 in c2 makes r11-12 white as well. Then a little LL.

Deep internal edge logic on the 5 in c2 versus c5 makes r13 white. (It would create two blocks in c5 {r13 and r15} which conflicts with c5's lone last clue.)

Then line logic to finish.

Found to be solvable with moderate lookahead by infrapinklizzard.

thx Joe, that was my solution

I had trouble seeing how R12C2 would be a dot with EL.

At that point, I did two-way logic with the 3 clue in R1. I looked at how C4 was affected. If it goes in the bottom section, then R18C4 is a dot, making R14C4 black. If it goes in the top part, then R14C4 will also be black. So we can mark that one black.

EL on C3 makes R19-20C3 dots. LL to finish.

Nice solve.

thx Gator

Guess I started this one wrong because I wound up doing a lot of guessing.

Not fun.

fun to solve. interesting solution. no quessing.

Goto next topic

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