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#1: Kristen Vognild (Kristen) on Feb 3, 2013 [HINT] [SPOILER]

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lol..sneaky edge logic :)

here were my steps:

EL dots C20R1-2
LL
EL dots C1R1 because of R3
then more normal EL dots C2-4R1 and C16-17R1
also EL dots C10R1

that leaves two places the 5 can go. either way will trigger both 3's in R2, so we know that either way C9-11R2 are black and C1,2,6,7,8,12,13,17R2 are dots.

LL
C7R7 or C10R7 must be black, the resulting dots in R8 mean that the 8 must start no further left than C8. C12-15R8 are black.
LL to finish.

I also solved with EL on the right side five!

I started el on the 5 in c 20 also...but knew I could dot r10 c20 as well cuz if the 5 made it to the bottom, then the 8 and 6 in the bottom rows would cause a discrepancy with the 1's in the c's....and also that either that 8 or 6 had to start at least as far right as c17, so the ll dots above had to be part of the 2's and not the 1's. just another way of many to tackle this puzzle...good solve Tom!

Thanks, all!

Love how it gets rated 2 in difficulty... I try to be sneaky with the logic ;)

Tom, you keep forgetting that there are people out there (it might ever be Karl) who love to mess with the ratings. Forget the ratings, listen to your friends.

Kristen, it cannot be started by looking at the 5 & 3s in r1-2. There are two places that they can be put with no conflict til much later (c5-9 & c11-15).

David - good catch on the 8 in r8 - that's where I got stuck.

It can so, because that's where I started it :D

:) @ kristen

most excellent

most excellent

Found to be solvable with moderate lookahead by infrapinklizzard.

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