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Comments on Puzzle #20228: Restrain Yourself
By David Bouldin (dbouldin)

peek at solution       solve puzzle
  quality:   difficulty:   solvability: moderate lookahead  

Puzzle Description:

...or I'll have to do it for you.

#1: valerie o..travis (bigblue) on Feb 3, 2013

good solve and image david :)
#2: Norma Dee (norm0908) on Feb 3, 2013
ditto #1
#3: Aldege Cholette (aldege) on Feb 3, 2013
Ditto #2,and a bit kinky too David.:)
#4: John Macdonald (perlwolf) on Feb 3, 2013 [SPOILER]
I'll just make an off-the-cuff remark...
#5: Teresa K (fasstar) on Feb 5, 2013
Really nice puzzle, David. I've never seen any up that close before. :-)
#6: David Bouldin (dbouldin) on Feb 6, 2013
thanks everybody.
al, not unintentional.
teresa, suuuuure you haven't ;)
#7: Brian Bellis (mootpoint) on Oct 23, 2017
Or this could have been called free at last if they had just been removed.
#8: Wombat (wombatilim) on Mar 22, 2023 [HINT]
Initial LL places exactly 1 pixel.

C15: EL places black in R19-22. LL.
C1: EL places black in R4-6. LL.
R1: EL marks C9 white. LL.
R1: Deep EL (v.R4) marks C10-14 white. LL.
C13: EL marks R2-3 white. LL.

R12: If the 2 does not connect to C8-10, the 2s in R13-14 will have nowhere to go in 2 steps, so C2-6 and C12-14 in R12 are white. LL.

R25: EL marks C8 white.
R16: If the 3 goes into C2, it will make R17 invalid, so R16C2 is white. Minimal LL.
R17: If the 8 goes into C3, it will make R16 or R18 invalid, so R17 C2-3 are white. LL.
R18: If the 5 goes into C3, it will make R19 invalid, so R18 C2-3 are white. LL.

C11: If the black in R17 is the 1, it makes C6 invalid, so it must be part of a 3. LL.

C15: If the 6 goes into R24, it makes R25 invalid, so R18C15 must be black. LL.

R14: Whichever way the 2 goes, in 1 step R11C10 is white. In 2 steps, the 2 in R10 is placed in either C7-8 or in C11-12, and either of these will start the 2 in R9. In R10 this marks C2-6, C9, and C13-14 white, and in R9 this marks C2-7, C10, and C13-14 white.

LL to finish.
#9: Web Paint-By-Number Robot (webpbn) on Mar 22, 2023
Found to be solvable with moderate lookahead by wombatilim.

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