Puzzle Description:

of the Pythagorean Theorem.

#1: Brian Bellis (mootpoint) on Jul 2, 2012 [SPOILER]

Given: Four identical triangles with sides A and B and hypotenuse C.
1. Area of box = C^2
2. Area of each pair of triangles = AB
3. Area of all four triangles = 2AB
4. Area of white middle square = (A-B)^2
5. Area of white middle square = A^2 - 2AB + B^2
6. Area of box = area of all four triangles + area of white middle square
7. C^2 = (2AB) + (A^2 - 2AB + B^2)
8. C^2 = A^2 + B^2

First time I see this demonstration... awesome

Also makes a fun quilt square!

its greek to me

The visual makes the math so much easier to understand. Very cool puzzle, Brian. Nicely designed.

Thank you.

good one:)

Thanks.

Very cool. I can't remember if I had ever learned that before or not, but I enjoyed relearning it if I had!

When I took Geometry my favorite stuff was the "constructions" using a compass and straight edge. I spent many hours trying to trisect an angle because my teacher said it was impossible.

An exceptional image to explain the theorem. Bravo!

You CAN trisect a straight angle by using Euclid's first Theorem.

I like it

I'd always considered making a puzzle like this, but I wondered how. I don't have to any more--nicely done!

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