peek at solution solve puzzle
quality: difficulty: solvability: line & color logic only
Puzzle Description Suppressed:Click below to view spoilers
#1: David Bouldin (dbouldin) on Apr 10, 2012 [SPOILER]
Comment Suppressed:Click below to view spoilers#2: Joe (infrapinklizzard) on Apr 10, 2012 [HINT]
I'm not a mathematician, so I don't have the tools to generate a proof, but I'm nearly certain that this must be true. The rub is that you cannot assume that any particular puzzle on this site *has* a unique solution.#3: David Bouldin (dbouldin) on Apr 11, 2012 [HINT]
As to assuming symmetry -
If the clues available are symmetrical in one direction,
AND in the other direction, all lines:
-- have an even number of clues that are symmetrical
-OR-
--have an odd number of clues where all but the center clue is symmetrical AND the "center" clue is a number that has the same parity* as the number of rows or columns in that direction,
then it's a good bet that it's symmetrical. (NB for noobs: assuming symmetry is not considered good logic on this site.)
While this puzzle shows symmetry in the column clues, the rows are beyond a doubt asymmetrical.
* -- By parity, I mean the quality of oddness vs evenness. (Eg. if the number of rows is odd, then any "center" clue for a column must then be odd if the puzzle is to be symmetrical. If the row count is even, then any column "center" clue must be even. )
-- The same idea goes in column vs row situations.
agree joe. i capitalized "WITH ONLY ONE SOLUTION" because that's a big assumption that you must know that going in, which on this site means that the creator must include this information in the title. agree whole-heartedly with your note for noobs.#4: Joe (infrapinklizzard) on Apr 11, 2012 [HINT]
David, you must have posted while I was musing. I did not see your first post until now.#5: Tom O'Connell (sensei69) on Apr 16, 2012
It was much more succinct than mine. The only thing I added was the requirement about the matching parity of the center clue.
huh.... lol
Show: Spoilers
You must register and log in to be able to participate in this discussion.