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#1: Joe (infrapinklizzard) on Oct 28, 2022 [SPOILER]

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After LL/CL finishes most of it (97%) leaving some green in the upper right and red in the lower left,

Summing for the green:
Since there must be at least seven more pixels of green in columns 24-31, and there is only one 1 in r4, r3 must have at least six green pixels in it. (and since it's a blob clue, they must be contiguous)
Therefore r3c26-29 must be green

LL finishes the green

Summing for the red is a little more complicated because of the blob in c6. So instead of summing for the whole of the unknowns, let's restrict it:

We'll look at the box of [r29-30 x c5-13]
> according to the vertical clues, there must be at least 8 more red pixels within that rectangle.
> The horizontal clues for those two rows are 1 and a blot.
= Therefore the blot must extend at least seven more pixels
SO r30c5-11 must be red

LL finishes the puzzle

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Found to be solvable with moderate lookahead by infrapinklizzard.

Nice!

Thank you for this. I needed to know. I'm telling all my friends. ;-)

Love it. I guessed Mondrian as I was working on it. I am not sure if I did it logically. It was fun though.

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