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Comments on Puzzle #11987: wcp#77 gotcha!
By Aldege Cholette (Aldege)

peek at solution       solve puzzle
  quality:   difficulty:   solvability: moderate lookahead  

Puzzle Description Suppressed:Click below to view spoilers

#1: Kristen Vognild (kristen) on Jan 31, 2011 [SPOILER]

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#2: Bryan (Cyclone) on Jan 31, 2011 [HINT]
PRIOR STARTING STEP EDITED OUT - UNNEEDED

You can solve a few starting points logically. After this, R9C6-9 is false. If true, it forces 2 true squares in R10. R9 is now solved, and the rest is a piece of cake. I've classified as solvable by logic.
#3: Tom O'Connell (sensei69) on Jan 31, 2011
i agree with Bryan... thx 4 entry
#4: bugaboo (bugaboo) on Jan 31, 2011
cyclone your first step is more than 2 look ahead moves just fyi
but yes this is logically solvable
#5: Bryan (Cyclone) on Jan 31, 2011 [HINT]
Actually, there are a few easily entered starting points before this at R4C4, R8C5, and R7C7 (all true). I'm editing out a step in my prior post because it's not necessary.
#6: Niki Cholette (Niki420) on Jan 31, 2011
this is solvable by logic alone as most can see now and it still has a ?
#7: Jota (jota) on Jan 31, 2011
No guessing for me ... great follow up story. Thanks!
#8: Meira Bracha (mbracha) on Feb 1, 2011
great drawing on a small palette.
#9: Aldege Cholette (aldege) on Feb 1, 2011
Thanks jota and Meira, I just couldn't resist putting a fish on the end of gator's hook.
#10: Wombat (wombatilim) on Feb 1, 2011 [HINT]
Bryan - I could indeed solve this easily assuming #2 is correct, but I couldn't see how you came to the conclusion that having R9C6-9 filled in would cause a contradiction in R10. Could you spell this out more clearly?

I did see that R8C1 had to be empty and R8C6 had to be filled in, since that would be true regardless of which side of C5 the 4 in R9 fell on.
#11: Kadou (Kadou) on Feb 1, 2011 [HINT]
Solves with logic alone. If you prefer edge logic, use it on column 9 for rows 8, 9, 10. They all end up in dots, therefore leaving room for the '4' clue on row 9 in columns 1 to 4 only.
#12: Wombat (wombatilim) on Feb 2, 2011
#11 Okay, that solved it for me, though still quite tricky. Thanks. :)
#13: Gator (Gator) on Feb 4, 2011 [HINT] [SPOILER]
Comment Suppressed:Click below to view spoilers
#14: Web Paint-By-Number Robot (webpbn) on Feb 4, 2011
Found to be logically solvable by Gator.
#15: Tom O'Connell (sensei69) on Feb 4, 2011
thanks for your agreement, gator
#16: Aldege Cholette (aldege) on Feb 4, 2011
Thanks Gator,i'm glad it was solvable.I used a different bait.lol
#17: Bryan (Cyclone) on Feb 13, 2011 [HINT]
Wombat, Gator seems to have used the same method I did solving for R9. However, I was able to use basic logic, I believe, up to that point and Gator's first step with R3 is not necessary; it actually solved itself after I solved R9. If my method still confuses you, I can get pictures.
#18: Sarah Andrews (sarah) on Feb 14, 2011 [SPOILER]
Comment Suppressed:Click below to view spoilers
#19: Aldege Cholette (aldege) on Feb 14, 2011
thx Sarah.
#20: Lilly Johns (LJohns315) on Jun 10, 2011 [SPOILER]
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#21: Aldege Cholette (aldege) on Sep 10, 2011
thx Lilly,very clever BTW.:)
#22: Joe (infrapinklizzard) on Jan 26, 2014 [HINT]
I only used one bit of advanced logic:

After line logic, deep edge logic on the 4 in r9 (vs r7).

If it were to go in c5-9, then the crossing clues of 2 in c6 and c8 would leave a block of one in r7. So r9c5-9 is white and it finishes with line logic.

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